Question

if 13 sin A=12, find sec A-tanA​

Answer 1

Answer:

1/5

Step-by-step explanation:

13 sin A = 12

sin A = 12/13 = opp./hyp.

(Hyp)^2 = (Opp)^2 + (Adj)^2

(adj)^2 = (13)^2-(12)^2

= 169-144

= 25

adj = √25 = 5

Now,

secA = hyp./adj = 13/5

tanA = opp./adj. = 12/5

secA-tanA = 13/5 - 12/5

= (13-12)/5

= 1/5

Hope it helps you...