Question

if 13 sin A=5 A is a acute angle. find 5 sinA - 2 cosA​

Answer 1

Answer:

1/13

Step-by-step explanation:

13 sin A=5

sin A = 5/13

sin²A + cos²A = 1

(5/13)² + cos²A = 1

25/169 + cos²A = 1

cos²A = 1 - 25/169

cos²A = 144/169

cos A = √144/169

cos A = 12/13

Now,

5sinA - 2cosA​

5 × 5/13 - 2 ×12/13

25/13 - 24/13

1/13