Question

If 13 sin A=5and angel A is acute find the value of 5sin A -2cosA÷tanA

Answer 1

If 13 sin A= 5
sinA= 5/13
sinA square + cosA square = 1
(5/13)square + cosA square = 1
25/169 cosA square = 1
cosA square = 1 - 25/169
cosA square = 169-25/169
cosA square = 144/169
cosA= √144/169
cosA = 12/13

Now
tanA= sinA/cosA
tanA= 5/12//12/13
tanA= 65/144

5sin A -2cosA÷tanA
5-2*12/13÷65/144
5-2*12*144÷13*65
5-3456÷845
4225-3456÷845
769/845

answer is 769/845