if (13-x) is the mean proportional of ( 9-x) and19-x then find value of x
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(13– x) is the mean proportional of (9 – x) and (19-x). [Given]
(9 -x) / (13- x) = (13-x) / (19- x)
(9 -x) - (13- x) / (13- x) = (13-x) - (19- x)/ (19-x)
9 -x - 13+ x) / (13- x) = 13-x - 19+ x / 19-x
∴ -4 (19 – x) = -6 (13 – x)
∴ -76 + 4x = - 78 + 6x
∴ 2x = 2
∴ x = 1
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