Math, asked by mayuri1234766, 21 days ago

If 13sin A - 12cos A = 0find the values of i) tan^2 A - sec^2 A.​

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Answered by shiney39
1

Answer:

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If 5cosθ−12sinθ=0, find

2cosθ−sinθ

sinθ+cosθ

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Solution

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5cosθ−12sinθ=0

⇒5cosθ=12sinθ

⇒cotθ=

5

12

2cosθ−sinθ

sinθ+cosθ

=

sinθ(2cotθ−1)

sinθ(1+cotθ)

=

5

12

−1

1+

5

12

=

5

24

−1

5

17

=

5

24−5

5

17

=

5

17

×

19

5

=

19

17

Hence, the answer is

19

17

.

Answered by shindesarthak796
2

If 13sin A - 12cos A = 0find the values of i) tan^2 A - sec^2 A.

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