Question

If 13sin theta = 5
find,
5 sin theta - 2 cos theta
tan theta​

Answer 1

$13Sin\alpha$ = 5

$sin\alpha$ = $\frac{5}{13}$=$\frac{opposite side}{Hypotenuse}$

$Cos\alpha$=$\frac{12}{13}$=$\frac{adjesent}{hypotenuse}$

we have to find  $5Sin\alpha -2Cos \alpha$

i) $5Sin\alpha -2Cos \alpha$

5($\frac{5}{13}$)-2($\frac{12}{13}$)

$\frac{1}{13}$ - $\frac{6}{13}$

$\frac{-5}{13}$

Thank you