Question

If 13sinA=5 A is a acute angle find 5sinA-2cosA÷tanA

Answer 1

now,

(5sinA-2cosA)/tanA

=(5×5/13 - 2×12/13)5/12

=(25/13 - 24/13)5/12

=(1/13)/(5/12)

=(1×12)/(13×5)

=12/65

Hope this may help u.....