Question

if 13x+10=-3x+42,then the value of "x" is​

Answer 1

13X+10=-3X+42

13X+3X=42-10

16X=32

x=32/16

x=2

Answer 2

Answer:

$\Large\boxed{\mathsf{X=2}}}$

Step-by-step explanation:

$\Large\boxed{\mathsf{SUBJECT: MATH}}$

TO FIND:

The value of x.

Isolate by the x from one side of the equation.

SOLUTIONS:

First, subtract by 10 from both sides.

$\displaystyle \mathsf{13x+10-10=-3x+42-10}$

Solve.

Subtract.

$\displaystyle \mathsf{42-10=32}$

$\displaystyle \mathsf{13x=-3x+32}}$

Then, you add by 3x from both sides.

$\displaystyle \mathsf{13x+3x=-3x+32+3x}}$

Solve.

Add.

$\displaystyle \mathsf{13+3=16}$

$\displaystyle \mathsf{16x=32}}$

Divide by 16 from both sides.

$\displaystyle \mathsf{\frac{16x}{16}=\frac{32}{16}}}$

Solve.

Divide the numbers from left to right.

$\Large\boxed{\mathsf{X=2 }}$

As a result, the final answer is x=2.