Question

if 13x-12y-32=0 and 12x-13y=28 than find the value of (x+y) and (x-y) ​

Answer 1

Answer:

13x-12y-32=0

13x-12y=32.....(1)

12x-13y=28.....(2)

adding equation 1 and 2

13x-12y=32

+12x-13y=28

_____________

25x-25y=60

divide both sides by 5

5x-5y=13....(3)

subtract equation 2 from 1

13x-12y =32

- 12x-13y=28

_____________

x+y=4......(4)

multiple equation 4 by 5

5x+5y=20...(5)

adding equation 5 and 3

5x+5y=20

+5x-5y=13

_____________

10x=7

x=7/10

substitute x=7/10 in equation 4

x+y=4

7/10+y=4

y=4 -7

__

10

y=40-7/10

y=33/10

Step-by-step explanation:

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