Question

if 13x+15y=41 and 15x+13y=43 find the value of (x,y)

Answer 1

Step-by-step explanation:

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SEE THE ATTACHMENT MY FRIEND....

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Answer 2

$13x + 15y = 41 \: \: \: - eqn \: 1 \\ 15 + 13y = 43 \: \: \: - eqn \: 2 \\ adding \: eqn \: 1 \: and \: eqn \: 2 \\ 13x + 15y = 41 \ \\ + 15x + 13y = 43 \\ = 28x + 28y = 84 \: ....eqn \: 3 \\ dividing \: eqn \: 3 \: by \: 28 \\ \: x + y = 3......eqn \: 4 \\ subtracting \: eqn \: 2 \: from \: eqn \: 1 \\ 15x + 13y = 43 \\ - \: 13x + 15y = 41 \\ = 2x - 2y = 2......eqn \: 5 \\ dividing \: eqn \: 5 \: by \: 2 \\ x - y = 1......eqn \: 6 \\ adding \: eqn \: 4 \: and \: eqn \: 6 \\ x + y = 3 \\ + x - y = 1 \\ 2x = 4 \\ x = \frac{4}{2} \\ x = 2 \\ substituting \: x = 2 \: in \: eqn \: 4 \\ x + y = 3 \\ 2 + y = 3 \\ y = 3 - 2 \\ y = 1$

Therefore x=2 and y=1 is the solution for the given equation...

hope this helps:)