Question

if 13x - 5=7x +11 then x =​

Answer 1

Answer:

13x-5=7x+11(arrange all common in one side)

13x-7x=11+5

6x=16

x=16/6

x=8/3

I hope this help you

Answer 2

Step-by-step explanation:

we can see from the question that multiple roots are possible.

M^N=1 the equation can be satisfied by M=1,-1 or N=0 or integer

case-1:

lets consider if M=1,

x^2-7x+11= 01

x^2-7x =10=0

(x-2)(x-5)=0

x= 2, 5

N= 0 >>>>X^2-13x+42= 0

(x-6)(x-7)= 0,

x= 6,7

so roots = 2,5,6,7

case-2:

now consider other condition

M= -1, then N=even,

x^2-7x+11= -1

x^2-7x+12= 0

(x-3)(x-4)=0

x= 3,4

hence no. of total roots = 6