Question

if 13y6 a is a multiple of 6 where why is a digit what is a possible value of Y​

Answer 1

Answer:

If it is divisible by 6 it must divisible by 2 and 3 both.

Since, in this number it's unit digit is even it is divisible by 2.

For divisible by 3 it's digits must sum upto a number which is a multiple of 3.

So, satisfying this situation we find values of f as 2 , 5 and 8.

Answer 2

Answer:

to find the value of y:

divisibility test=the digit is divided by 2 and 3 both

so: 13y6 is divisible by 2 as its last digit is 6

now by 3=1+3+y+6=10+y

10+y=12

y=12-10

=2

so ,y=2