Question

if -14/63=x/9=-18/y the (x,y)=​

Answer 1

Question:-

$\tt\implies\dfrac{ - 14}{63} = \dfrac{x}{9} = \dfrac{ - 18}{y}$

find the value of (x,y)

Solution:-

$\tt\implies\dfrac{ - 14}{63} = \dfrac{x}{9} = \dfrac{ - 18}{y}$

they are equal to each other ,so we can write

$\tt\implies\dfrac{ - 14}{63} = \dfrac{x}{9} \: \: and \: \: \dfrac{ - 14}{63} = \dfrac{ - 18}{y}$

first of all find the value of x

$\tt\implies\dfrac{ - 14}{63} = \dfrac{x}{9}$

$\tt\implies\dfrac{ - 14}{ \not63 {}^{} } = \dfrac{x}{ \not9}$

now we can write

$\tt\implies\dfrac{ - 14}{7} = x$

$\tt\implies x = \dfrac { - \not14}{ \not7}$

$\tt\implies x= -2$

now we have find value of y, we get

$\tt\implies\dfrac{ - 14}{63} = \dfrac{ - 18}{y}$

using cross multiplication

$\tt\implies -14\times y= -18\times63$

$\tt\implies -14y= -1134$

$\tt\implies y = \dfrac{ \not - 1134}{ \not - 14}$

$\tt\implies y=81$

value of x= -2 and y= 81