Question

if 14 kg of lpg gas is filled in your gas cylinder, calculate the total moles of lpg gas present in it​

Answer 1

Answer:

Correct option is

D

V=2.447m

3

Weight of full cylinder=29kg

Weight after usage=23.2kg

Gas consumed=29−23.2=5.8kgor5800g

For butane (C

4

H

10

),M=58

Normal pressure=1atm

Room temperature=298K

PV=nRT

or 1×V=

58

5800

×0.0821×298

or V=2446.58L≈2.447m

3

Hence, the correct option is D

Explanation:

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