Question

If 143.5 g of AgCl added to 1000 ml H20, then 142.065 g of AgCl was precipitated, and remaining amount of AgCl was dissolved in H20; what will be the molarity of solution?​

Answer 1

Answer:

0.01molar

Explanation:

m=143.5-142.65=1.435

n=1.435/143.32=0.01

M=0.01/1=0.01