Question

if 14g of nitrogen gas is mixed with 6g of hydrogen gas,then the maximum mass of ammonia produced in the reaction is​

Answer 1

The chemical reaction can be given as :

Nitrogen + Hydrogen ---> Ammonia

N2+ 3H2----> 2NH3

28g of nitrogen reacts with 6g of water to produce 36 grams of water

1 mole of N2 + 3 moles of hydrogen ---> 2 moles of water

moles of N2 = 14x1mole/28 =1/2 mole of N2

moles of hydrogen=4x1mole/2=2 moles of hydrogen

Based on mole ration, enough H2 is present , limiting reactant is N2 and excess reactant is H2

So,

28 g of N2----> 36 g of Water

14g of N2--------?

= 14x36/28

= 18 grams of water

Therefore when 14g of ammonia reacts mass of water

produced is 18g..