Question

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?

$\huge{{\underline{{\sf{\purple{Thinkew}}}}}}$ @siddhi163

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Answer 1

Given :

➝15.0 L of neon at 25.0 °C which is allowed to expand to 45.0 L

To Find :

➝New Temperature which can maintain constant pressure = ?!

Solution :

Let's solve this !

• As we know ! P×V = NRT

That means ➝ PV = NRT

➝ P = NRT / V

➝ P = 1 mol × 0.0821 × 298k / 151

➝ P = 1.63 Atom

• Now let's Move forward !

➝ T = PV/ NR

➝ T = 1.63 Atom × 451 / 1 mol × 0.0821

➝ T = 893 K

• ➝ Convert K into °C

➝893 K = 620°C

So, The new temperature to maintain the constant temperature is 620°C .

Answer 2

Answer:

If

Known and Unknown

V₁ = 15.0 L

T₁ = 25 °C + 273.15 = 298.15 K

V₂ = 45.0 L

T₂ = ? K

Solve for T₂.

T₂ = V₂T₁/V₁

T₂ = (45.0 L × 298.15 K)/(15.0 L) = 894 K

Step-by-step explanation:

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