Question

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?​

Answer 1

Vaibhav sorry yrr aaja płzzz❤

$\therefore\:{\underline{\sf{Answer~ -}}}$

Given :-

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters

To Find :-

New temperature

Solution :-

We know that

0⁰ C = 273⁰ K

Volume/Temperature = Volume/Temperature

15/298 = 45/T

15 × T = 45 × 298

15T = 13,410

T = 13410/15

T = 894⁰ K

Now

0⁰ C = 273⁰ K

894⁰ K = 894 - 273 = 621⁰ C

$\begin{gathered} \\ \end{gathered}$

Hope Helps..!!

Answer 2

Question:

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?

Answer:

$\sf{pv = nrt} \\ \\ \sf{p = \frac{nrt}{v} } \\ \\ \sf{p = \frac{1 mol \times 0.0821 \times 298k}{15l} } \\ \\ \sf{p = 1.63atom} \\ \sf{t = \frac{pv}{nr} } \\ \sf{t = \frac{1.63atom \times 45l}{1mol \times 0.0821} } \\ \sf{t = 893k} \\ \sf{ = 620 \degree c}$