Question

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?
​
What will be final answer ?¿?

Answer 1

Given:-

15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters.

Which means

• Volume of Neon (V₁ )= 15 L
• Temperature (T₁)= 25°C = 25×274.15° = 298.15
• Volume (V₂)= 45 L

To Find:-

• The new temperature be to maintain constant pressure . i.e, T₂

Solution:-

According to charles law :-

the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Now,

using charles law

$\frac{v _ 1}{t_{2} } = \frac{v _{2} }{t_{2} }$

Now Substituting the values given in the Question

$= > \frac{15}{298.15} = \frac{45}{t _{2} }$

$= > t _{2} = \frac{45 \times 298.15}{15}$

$= > t _{2} = 3 \times 298.15$

$= > t _{2} = 894.45k$

∴ 894.45K is the new temperature be to maintain constant pressure.

Answer 2

Step-by-step explanation:

refer to the above attachment