If 15(2x² - y2) = 7xy and x, y are positive,
then find x:y.
Answers
Answered by
1
Answer:
30X^2_15y^2=7xy
Step-by-step explanation:
x^2_y^2=7xy_60x+225y
Answered by
16
Answer:
here your answer
x = 5
y = 6
Step-by-step explanation:
Given:-
15 ( 2x^2 - y^2 ) = 7xy
30x^2 - 15y^2 = 7xy
30x^2 - 7xy - 15y^2 = 0
30x^2 - 25xy + 18xy - 15y^2 = 0
5x( 6x - 5y ) + 3y( 6x - 5y ) = 0
( 6x - 5y ) ( 5x + 3y ) = 0
6x - 5y = 0 ; 5x + 3y = 0
6x = 5y ; 5x = -3y
x/y = 5/6 ; x/y = -3/5
x : y = 5 : 6 ; x : y = -3 : 5
therefore the values of x and y positive
So,
x = 5.
y = 6.
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