Question

If 15(2x² - y2) = 7xy and x, y are positive,
then find x:y.
​

Answer 1

Answer:

30X^2_15y^2=7xy

Step-by-step explanation:

x^2_y^2=7xy_60x+225y

Answer 2

Answer:

here your answer

x = 5

y = 6

Step-by-step explanation:

Given:-

15 ( 2x^2 - y^2 ) = 7xy

30x^2 - 15y^2 = 7xy

30x^2 - 7xy - 15y^2 = 0

30x^2 - 25xy + 18xy - 15y^2 = 0

5x( 6x - 5y ) + 3y( 6x - 5y ) = 0

( 6x - 5y ) ( 5x + 3y ) = 0

6x - 5y = 0 ; 5x + 3y = 0

6x = 5y ; 5x = -3y

x/y = 5/6 ; x/y = -3/5

x : y = 5 : 6 ; x : y = -3 : 5

therefore the values of x and y positive

So,

x = 5.

y = 6.