Question

If 15 a² + 4 b²/ 15 a² - 4 b² = 47/7 then find the values of :(i) a/b (ii) b²−2a²/b²+2a²​

Answer 1

Answer:

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Step-by-step explanation:

Consider, a

2

+b

2

+c

2

–ab–bc–ca=0

Multiply both sides with 2, we get

2(a

2

+b

2

+c

2

–ab–bc–ca)=0

⇒ 2a

2

+2b

2

+2c

2

–2ab–2bc–2ca=0

⇒ (a

2

–2ab+b

2

)+(b

2

–2bc+c

2

)+(c

2

–2ca+a

2

)=0

⇒ (a–b)

2

+(b–c)

2

+(c–a)

2

=0

Since the sum of square is zero then each term should be zero

⇒ (a–b)

2

=0,(b–c)

2

=0,(c–a)

2

=0

⇒ (a–b)=0,(b–c)=0,(c–a)=0

⇒ a=b,b=c,c=a

∴ a=b=c.