If 15 cot 0 = 8, then find the value of
(1 - sin 0) (1 + sin o)
(1 + cos 0) (1 - cos 0)
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Answer:
i 64/289
ii 225/289
Step-by-step explanation:
cot theta = 8/15
which means base / perpendicular
by Pythagoras theorem,
H^2= 64 + 225
H^2=289
H=17
Now,
Sin theta = p/h= 15/17 and cos theta= b/h = 8/17
(1-Sino)(1+Sino)= (1-Sino)^2= Cos^2theta
(8/17)^2=64/289
ii,
(1+Cos0)(1-Cos0)=(1-Cos0)^2=Sin^2theta
(15/17)^2= 225/289
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