If 15 cot A= 8, find Sin A and Sec A.
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Answer:
SinA = 15/17 SecA = 17/8
Explanation:
15cotA = 8
cotA = 8/15
thus perpendicular = 15 base = 8 hypotenuse = 17(using Pythagoras theorem )
thus sinA = 15/17
seca = 17/8
Answered by
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15 cot A=8
cot A=8/15 means base =8 and perpendicular=15
H ^2=P^2+B^2
H^2=15^2+8^2
H^2=225+64
H^2=289
H=√289=17
sinA = P/H
=15/17
secA = H/B
=17/8
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