If 15 February 2010 was Monday, what was the day on 10 January 2006?
Answers
Step-by-step explanation:
On 31st December, 2005 it was Saturday. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday.
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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010
The required day on 10 January 2006 will be Wednesday.
Step-by-step explanation:
Given:
15 February 2010 was Monday.
To Find:
The day on 10 January 2006.
Solution:
As given-15 February 2010 was Monday.
Odd days of a year P = Remainder of [No. of days in the year P/ 7].
Where 7 is for every 7 days, the day will be repeated, because of this dividing the total number of days of an year by 7. If it has any remainder then it will be considered as an odd day for that year.
The required remainders (odd days) for the different years are as per following;
For 2010: 365/7 = 1 (Total no. of days in 2006 is 365)
For 2009: 365/7 = 1
For 2008: 366/7 = 2 (Leap year, hence Feb month has 29 days)
For 2007: 365/7 = 1
For 2006: 365/7 = 1
Therefore, total number of odd days = 6.
Given day is ' Monday' and total no of odd days is '6'.
The day on 15 February 2006 = Monday - 6
= (The 6th day back to Monday)
== Monday, 1- Sunday , 2-Saturday , 3-Friday , 4-Thursday ,5-Wednesday ,6-Tuesday.
The day on 15 February 2006 is Tuesday.
The required day on 10 January 2006 will be Wednesday.
Thus,the required day on 10 January 2006 will be Wednesday.
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