Question

If 15 g of sulphur is burnt then what volume of SO2 would be produced at STP?

Answer 1

S + O2 → SO2

Here 32g sulfur reacts with 32g of oxygen and produces 64g sulfur dioxide.

So 15g of sulfur has 15/32 = 0.46 moles.

So 15g sulfur gives 0.46 moles of sulfur dioxide. The volume of sulfur dioxide will be at STP

0.46 = x / 22.4

X = 0.46 × 22.4

X = 10.304 L at STP.

Hope it helps!

Answer 2

Answer:

10.51

Explanation:

mole=givenvolume÷molar volume                                                                                   volume=mole×molar volume                                                                                            15×22.414=10.51