Question

if 15 gm air is heated from 0 degree to 5 degree at constant volume by adding 150 calories of heat, change in internal energy will be

Answer 1

Hey dear,

● Answer -

∆U = 605.5 J

● Explanation -

# Given -

W = 15 gm

T1 = 0 ℃

T2 = 5 ℃

Q = 150 cal = 627 kJ

# Solution -

Work done by heating air is calculated by -

W = -nR∆T

W = -15/29 × 8.314 × (5-0)

W = -21.5 J

Change in internal energy is calculated by -

∆U = Q + W

∆U = 627 - 21.5

∆U = 605.5 J

Therefore, change in internal energy iz 605.5 J.

Hope this is satisfactory.

Answer 2

Answer:

change in internal energy in 10 cal/gm

Explanation: