if 15 kg of mass relational 5 metre per second what is applying force solve on copy
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Answer:
We know that the resultant force (F)=
F
1
2
+F
2
2
+2F
1
F
2
cosθ
⇒F=
(5
2
)
2
+(6
2
)
2
+2(5
2
)(6
2
)cos60
0
⇒F=13.49N
⇒a=
m
F
=
1000
13.49
=0.01349m/s
2
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