Question

If 15 tan thetha = 8 find values of cos thetha and cosec thetha

Answer 1

Answer:

Here is your ans mate

Step-by-step explanation:

15 tan © = 8

tan © = 8/15

tan © = Perpendicular / Base

So,

Perpendicular = 8

Base = 15

Now,

By pythagorus theorem,

(Hypotenuse)² = (Perpendicular)² + (Base)²

(Hypotenuse)² = (8)² + (15)²

(Hypotenuse)² = 64 + 225

(Hypotenuse)² = 289

Hypotenuse = 17

Now,

cos © = Base / Hypotenuse

= 15/17

And,

cosec © = Hypotenuse / Perpendicular

= 17 / 8

Answer 2

Answer :-

$15tan\theta=8$

$tan\theta=\frac{P}{B} =\frac{8}{15}$

Pythagoras Theorem :-

$AC^{2}=AB^{2}+BC^{2}$

$=>AC^{2}=8^{2}+15^{2}$

$=>AC^{2}=64+225$

$=>AC^{2}=289$

$=>AC=\sqrt{289}$

$=>AC=17$

Hence,

$cos\theta=\frac{Base}{Hypotenuse}$

$=\frac{BC}{AC}$

$=\frac{15}{17}$

$cosec\theta=\frac{Hypotenuse}{Perpendicular}$

$=\frac{AC}{AB}$

$=\frac{17}{8}$

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