Question

If 15 tickets for a fair costs ₹ 105, how much shall I pay for

3 tickets​

Answer 1

Answer:

21

Step-by-step explanation:

if u divide 105 from 15 you'll get 7 which means 1 ticket costs ₹7

then multiply 3 to 7 which is equal to 21

Answer 2

Let fixed charge be Rs x and charge per km be Rs y.

⇒x + 10y = 105 ...(1)

⇒x + 15y = 155 ..(2)

Now From eq 2

⇒15y = 155 − x

⇒

$⇒y = \frac{155 - x}{15} \:\: ...(3) \\ substituting \: y \: from \: eq \: 3 \: in \: eq \: 1 \: \\ ⇒x + \frac{10(155 - x)}{15} = 105 \\ ⇒15x + 1550 - 10x = 1575 \\ ⇒5x = 1575 - 1550 \\ ⇒5x = 25 \\ ⇒x = 5 \\ \\ substituting \: x \: in \: eq \: 2 \\ ⇒5 + 15y = 155 \\ ⇒15y = 155 - 5 \\ ⇒15y = 150 \\ ⇒y = 10 \\ \\ hence \: x = 5 \: and \: y = 10$

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010 For 2525 km person have to pay

→ 5 + 10 × 25 = 255 Rs.

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