if 15C(2r-1)=15C(2r+4) find r
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the equation is wrong as :
Solving LHS
15c(2r-1)
30cr - 15c
Solving RHS
15c(2r+4)
30cr + 60c
equating RHS and LHS
30cr - 15c = 30cr + 60c
30cr - 30cr = 60c + 15c
0 = 75c
0 = c
Putting c=0 in the equation given in question,
15(0)(2r - 1) = 15(0)(2r + 4)
0 = 0
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find the value of if 15C(2r-1)=15C(2r+4) find r
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