Question

if 15cotA=6 then sinA =?​

Answer 1

Answer:

sinA=5/√29

Step-by-step explanation:

cotA =6/15

cotA= 2/5

by using Pythagoras theorem

hypotenuse= √29

sinA= 5/√29

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\implies 15 cotA=6 \\ \\ \sf\implies cot A=\frac{6}{15}$

Now find the value of tanA

$\sf\implies tan A=\frac{1}{cot A}\\ \\ \sf\implies tan A=\frac{1}{\frac{6}{15}}\\ \\ \sf\implies tan A=1\times \frac{15}{6}=\cancel{\frac{15}{6}}\\ \\ </p><p>\sf\implies tanA= \frac{5}{2}$

The value of tanA =5/2

$\boxed{\sf{\purple{tanA=\frac{perpendicular}{base}}}}$

• Perpendicular of triangle=5cm

• base= 2cm

• Now the hypotenuse

$\sf\implies hypotenuse {}^{2}=base{}^{2}+perpendicular {}^{2}\\ \\ \sf\implies hypotenuse{}^{2}= (5){}^{2}+(2){}^{2}\\ \\ \sf\implies hypotenuse=\sqrt{25+4}\\ \\ \sf\implies hypotenuse=\sqrt{29}$

• Hypotenuse=√29

Now the value of sinA

$\sf\implies{\blue{ sinA=\frac{perpendicular}{Hypotenuse}}}\\ \\ \sf\implies sinA=\frac{5}{\sqrt{29}}$

$\boxed{\sf{sinA=\frac{5}{\sqrt{29}}}}$