Question

if 15integer2/3×3integer1/6+11integer 7/8 +x then sum of digits of denominator of x in simplest form is
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Answer 1

Step-by-step explanation:

Let the two numbers be x and y.

As per the given condition, we have

2x+3y=89 ....(1)

and 4x=13+5y

⇒4x−5y=13 ....(2)

Multiply equation (1) by 2, we get

4x+6y=178 ....(3)

Subtract equations (2) and (3), we get

11y=165

⇒y=15

Put this value of y in equation (1),

2x+3(15)=89

⇒2x+45=89

⇒2x=44

⇒x=22

Therefore, the required numbers are 22 and 15.

Answer 2

Answer:

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