if 15th term of an AP is 101 and sum of the first 6 terms is 123 .find the sequences
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a15=101. S6=123
a+14d=101. =}6/2[a+a6]=123
a=101-14d. =}3[2a+5d]=123
=} 3[2(101-14d)+5d=123
=}3(201-28d)+5d=123
=}603- 84d+5d=123
=} -79d=123-603
=} d= 480/79 now put
the value of d in 1 eqn.
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