Question

If 15x+16y/25x+4y = 7/6, then find x:y

Answer 1

Answer:

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Answer 2

Answer:

Required ratio of x and y is 68 : 85.

Step-by-step explanation:

Here,

$\dfrac{15x+16y}{25x+4y}=\dfrac{7}{6}$

On left hand side : Divide and multiply by y

$\implies\dfrac{15x+16y}{25x+4y}\times\dfrac{y}{y}$$\implies\dfrac{\frac{15x+16y}{y}}{\frac{25x+4y}{y}}\\\\\\\implies\dfrac{\frac{15x}{y}+\frac{16y}{y}}{\frac{25x}{y}+\frac{4y}{y}}\\\\\\\implies\dfrac{\frac{15x}{y}+16}{\frac{25x}{y}+4}$

Now, left hand side is $\dfrac{\frac{15x}{y}+16}{\frac{25x}{y}+4}$ and right hand side is $\dfrac{7}{6}$

Thus,

$\implies\dfrac{\frac{15x}{y}+16}{\frac{25x}{y}+4}=\dfrac{7}{6}\\\\\\\implies 6\bigg( \dfrac{15x}{y} + 16 \bigg) = 7\bigg( \dfrac{25x}{y} + 4 \bigg) \\\\\\\implies \dfrac{90x}{y} + 96 = \dfrac{175x}{y} + 28 \\\\\\\implies 96 - 28 = \dfrac{85x}{y}\\\\\\\implies 68 = \dfrac{85x}{y}$

= > 68 / 85 = x / y

Hence the required ratio of x and y is 68 : 85.