Question

 If 16 2/3 % of a number is added with itself then result becomes 4956. Find the original Number.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Required value of x is $280 \frac{24}{53}$

Step-by-step explanation:

Let the number be x.

Now According to question,

$16 \frac{2}{3} \times x + x = 4956$

We are converting mixed fraction to improper fraction

$\frac{16 \times 3 + 2}{3} \times x + x = 4956$

$\frac{50}{3} \times x + x = 4956$

Adding all x variable by addition method of fraction,

$\frac{50x + 3x}{3} = 4956$

$\frac{53x}{3} = 4956$

By Cross multiplication,

$53x = 3 \times 4956$

$53x = \frac{14868}{1}$

$x = \frac{14868}{53} = 280 \frac{28}{53}$

Required value of x is $280 \frac{24}{53}$