If 16^3÷2+16^-3÷2=m , then find the value of m^-1
Answers
Answered by
1
Answer:
m
2
=27
2/3
×16−3/2
⇒m
2
=3
3×
3
2
×4
2×
2
−3
m
2
=3
2
×2
−6
⇒m=3×2
−3
=3/8
Answered by
2
Answer:
Refer to the attachment
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