Math, asked by anujkumaryadav0403, 7 hours ago

If 16^3÷2+16^-3÷2=m , then find the value of m^-1​

Answers

Answered by Abeeha55550
1

Answer:

m

2

=27

2/3

×16−3/2

⇒m

2

=3

3

2

×4

2

−3

m

2

=3

2

×2

−6

⇒m=3×2

−3

=3/8

Answered by amishayadav183
2

Answer:

Refer to the attachment

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