Question

if 16, ab and -8 are
in Ap find
a+b.​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

Given : 9, a, b,-6 are in AP.

To find : The value of a+b?

Solution :

9, a, b,-6 are in AP.

We know, common difference are constant.

So, a - 27 = b - a = -6 - ba−27=b−a=−6−b

i.e. 2a - b = 272a−b=27 ----------(1)

2b - a = -62b−a=−6 ----------(2)

Solve (1) and (2),

Multiply (2) by 2 and add (1),

2a - b+4b-2a = 27-122a−b+4b−2a=27−12

3b= 153b=15

b=5b=5

Put b in equation (1),

2a - 5 = 272a−5=27

2a=322a=32

a=16a=16

Now, a=16 and b=5

a+b=16+5=21a+b=16+5=21

Answer 2

Answer:

As the three terms are in Ap, we can say ab is the arithmetic mean of 16 and -8

ab=( 16+(-8))/2=4

ab=4

Now all possible values of a and b for which ab =4 are

a=4 b=1

a=1 b=4

a,b=2

And their negatives.

So possible values of a+b are 5,4 or -5 and -4.

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