Question

If 16 cot x is equals to 12 then sin x minus cos x by sin x + cos x is

Answer 1

Answer:

16cotX=12

cotX=12/16=3/4

sinx-cosx/sinx+cosX

DIVIDE BY SINX

sinx/sinx-cosx/sinx ÷ sinx/sinx+cosx/sinx

1-cotx/1+cotx

1-3/4÷1+3/4

1/4÷7/4

1/4×4/7

1/7

Step-by-step explanation:

Answer 2

The value of $\dfrac{\sin x - \cos x}{\sin x + \cos x}$  is   $\dfrac{1}{7}$

Step-by-step explanation:

Given : 16 cot x = 12

To find: The value of  $\dfrac{\sin x - \cos x}{\sin x + \cos x}$

Now as given

$16 \cot x = 12 \\\\\Rightarrow \cot x= \dfrac{12}{16} =\dfrac{3}{4}$

Now as according to question

$\dfrac{\sin x - \cos x}{\sin x + \cos x}$

Dividing the numerator and denominator by sinx we get

$\dfrac{\dfrac{\sin x - \cos x}{\sin x} }{\dfrac{\sin x + \cos x}{\sin x} }\\\\\\= \dfrac{1-\cot x}{1+\cot x}$

Substituting the value of cotx we get

$\dfrac{1-\dfrac{3}{4} }{1+\dfrac{3}{4}} =\dfrac{\dfrac{4-3}{4} }{\dfrac{4+3}{4}}= \dfrac{1}{7}$

Hence, the value of $\dfrac{\sin x - \cos x}{\sin x + \cos x}$  is   $\dfrac{1}{7}$

#Learn more

If tan x =3/4 , find sin x and cos x.​

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