If 16 grams of o2 react with excess c2h6, how many grams of co2 will be formed?
Answers
First the balanced equation is
C2H6+7/2O2=>2CO2+ 3H2O
Write no of moles from equation
7/2 mol of O2 produced 2 mol of CO2
Substitute mols by molecular mass
3.5 mol × 32 = 2 mol × 44
Mass of sample
16 gm = ????
Mass of co2
16× 88 ÷ 112 = 12.5 gm
Answer:
13 grams of CO2
Explanation:
2C2H6+7O2→4CO2+6H2O
First of all calculate moles of oxygen,
n=16/32
n=0.5
Now equates moles of oxygen with moles of carbon dioxide;
nO2/7=nCO2/4
0.5/7=nCO2/4
0.5*4/7=nCO2
0.3=nCO2
Now,we have moles and molar mass of CO2 and it is easy to calculate mass of CO2
nCO2=mass/molar mass
0.3=mass/44
0.3*44=m
13g=m
Hope you understood:)