Question

If 16 term of an



a.P is -10 and 10 term is -26 then find length 17 term of ap

Answer 1

a16=a+15d=-10. eq1

a10=a+9d=-26. eq2

From eq 1&2

d=(8÷3)&a=-50

S17=(17÷2)(2×-50+16×(8÷3))

By solving we get

S17=(-2476÷3)