Question

If 16, y, y, 81 are in proportion, find the value of y.
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Answer 1

$\bf \red{given}$

16, y, y, 81 are in proportion

To find out :

the value of y

solutions:

$\frac{16}{y} = \frac{y}{81}$

$y {}^{2} = 81\times 16$

$y {}^{2} = 1296$

$y = \sqrt{1296}$

$y = 36$

Answer 2

16 : y : y : 81

product of mean × product of extreme

y × y = 81 × 16..

y² = 1296

y= √1296

y = 36..

thanks for the answer please