Math, asked by ranjanalourembam0, 8 days ago

If 16³ × 9² divided by 16² 9² = a^n-1 what is the value of n ?​

Answers

Answered by aqeelsoban786
0

Step-by-step explanation:

16^3*9^2/16^2*9^2=a^n-1

16*16*16*9*9/16*16*9*9=a^n-1

16=a^n-1

2^4=a^n-1

as the exponent of 2 is 4 so

n-1=4

so

n=5

the value of n is 5

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