Question

if 16a + 16b=48,what is the average of a and b (answer in full solution)​

Answer 1

Answer:

3/2

step by step explaination:

Average of a and b = ( a + b ) /2 --( 1 )

16a + 16b = 48 [ given ]

Divide each term with 16 , we get

a + b = 3

Now ,

( a + b ) / 2 = 3/2

Therefore , average of a and b

= ( a + b ) /2 = 3/2

I hope this helps you.

:)