Question

If 16coa A=12 then find the value of sinA-cosA/sinA+cosA​

Answer 1

Answer:

1/7

Step by step :

If 16cotA=12

Then cotA =3/4 so now u can draw a right angled triangle and find sinA, cosA values

sinA=4/5,cosA=3/5

Now u can substitute the values....

Answer 2

$16cosa = 12 \\ \\ cosa = \frac{12}{16} = \frac{3}{4} \\ \\ sina = \sqrt{1 - \frac{9}{16} } \\ \\ = \sqrt{ \frac{7}{16} } = \frac{ \sqrt{7} }{4}$

Now

$\frac{sina - cosa}{sina + cosa} \\ \\ = \frac{ \frac{ \sqrt{7} }{4} - \frac{3}{4} }{ \frac{ \sqrt{7} }{4} + \frac{3}{4} } \\ \\ = \frac{ \sqrt{7} - 3}{ \sqrt{7} + 3}$