Question

If 16cot x =12, then sinx –cosx/Sinx+Cosx equal:​

Answer 1

Answer:

$\frac{13}{20}$

Step-by-step explanation:

$16cot x = 12\\=> cot x=\frac{12}{16}=\frac{b}{p}\\h^{2}=p^{2} + b^{2}\\=>h^{2}=16^{2} +12^{2} =256+144=400\\=> h=\sqrt{400} =20\\sin x- \frac{cosx}{sinx}+cosx=\frac{p}{h}-cotx+\frac{b}{h}\\=\frac{16}{20}-\frac{12}{16}+\frac{12}{20}\\=\frac{13}{20}$