Math, asked by pc561902, 20 hours ago

If 16cotx=12 , then find the value of sin x-cos x/ sin x + cos x
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Answers

Answered by BinayakStark
0

Answer:

cot x = 12/16

cot x = 3/4

Also cotθ = base/perpendicularSo we now construct a right triangle ABC, right angled at B such that∠BAC = θ, Base = 3 and perpendicular = 4 

In ∆ ABC,



AC2 = AB2 + BC2

AC2 = (3)2 + (4)2

AC2 = 9 + 16 = 25

AC = 5

As we know sinθ = perpendicular / hypotenuse 

cosθ = base / hypotenuse

Therefore,

sin x = AB/AC = 4/5

cos x = BC/AC = 3/5

Now,





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