If 16cotx=12 , then find the value of sin x-cos x/ sin x + cos x
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Answer:
cot x = 12/16
cot x = 3/4
Also cotθ = base/perpendicularSo we now construct a right triangle ABC, right angled at B such that∠BAC = θ, Base = 3 and perpendicular = 4
In ∆ ABC,

AC2 = AB2 + BC2
AC2 = (3)2 + (4)2
AC2 = 9 + 16 = 25
AC = 5
As we know sinθ = perpendicular / hypotenuse
cosθ = base / hypotenuse
Therefore,
sin x = AB/AC = 4/5
cos x = BC/AC = 3/5
Now,


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