If 16g of he is mixed with 32g of o2 then calculate heat capacity ratio of the mixture
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Given,
M
He
=4, m
he
=16g
M
ox
=32, m
ox
=16g
Specific heat of mixture at constant volume is given by,
C
V
=
n
1
+n
2
n
1
C
V
1
+n
2
C
V
2
. . . . .(1)
For Helium gas,
No. of moles, n
1
=
M
he
m
he
n
1
=
4
16
=4
γ
1
=
3
5
Foe Oxygen Gas,
no. of moles, n
2
=
M
ox
m
ox
n
2
=
32
16
=
2
1
γ
2
=
5
7
And specific heat constant volume of helium gas,
C
V
1
=
γ
1
−1
R
=
3
5
−1
R
=
2
3
R
The specific heat of oxygen at constant volume,
C
V
1
=
γ
2
−1
R
=
5
7
−1
R
=
2
5
R
From equation (1),
C
V
=
1
4
+
2
1
4×
2
3
R+
2
1
×
2
5
R
C
V
=
18
29
R=
γ−1
R
γ=
29
18
+1
C
V
C
P
=γ=1.62
The correct option is D.
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