Question

If 16th term is 16 more than 12th term of an AP find the common difference of the AP

Answer 1

please find your answer in the pic

Answer 2

Answer:

4

Step-by-step explanation:

The nth term of A.P. = $a_n=a+(n-1)d$

Substitute n = 16

$a_{16}=a+(16-1)d$

$a_{16}=a+15d$

Substitute n = 12

$a_{12}=a+(12-1)d$

$a_{12}=a+11d$

Since we are given that 16th term is 16 more than 12th term

So,  $a_{16}=a_{12}+16$

$a+15d=a+11d+16$

$15d=11d+16$

$15d-11d=16$

$4d=16$

$d=4$

hence the common differnece of given A.P. is 4