Question

if 16x^2-8x+1=0 when x=1/4y find value of y​

Answer 1

Answer:

y=1

Step-by-step explanation:

Given that x=1/4y

and 16x^2-8x+1=0

16(1/4y)^2-8(1/4y)+1=0

16(1/16y)-8(1/4y)+1=0

1/y -2/y+1=0 [16,8 were cancelled]

now take L.cm y

1-2+y/y=0

1-2+y=0(y will be multiplied with 0 and the value is 0)

y=1

Answer 2

Answer:

Y = 1

Step-by-step explanation: