Question

If 16x^2+kxy+25z^2 is a perfect square,find the value of 'k'?

Answer 1

(Your question:16x²+kxy+25y²?)

Step-by-step explanation:

Perfect square has double zero.

Discriminant for x: zero.

→ k²y²-16×25×4y²=0

→ k²y²-1600y²=0

→ y²(k²-1600)=0

→ k²-1600=0 [A variable y is ignored.]

∴k=±40

Answer 2

Answer:

as we are seeing that in the question 8t can be seen that identity (a+b)^2 was used . by using it , it can be found the answer will be 40

Step-by-step explanation:

so , it can be done

(a+b)^2= a^2+ 2ab +b^2

(4x+5z)^2=16x^2+2×4x×5z+25z^2

............,,........

by doing this further We find the answer 40.

thanks